-[8-(12z+2)]=2+(3z+0)

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Solution for -[8-(12z+2)]=2+(3z+0) equation:


Simplifying
-1[8 + -1(12z + 2)] = 2 + (3z + 0)

Reorder the terms:
-1[8 + -1(2 + 12z)] = 2 + (3z + 0)
-1[8 + (2 * -1 + 12z * -1)] = 2 + (3z + 0)
-1[8 + (-2 + -12z)] = 2 + (3z + 0)

Combine like terms: 8 + -2 = 6
-1[6 + -12z] = 2 + (3z + 0)
[6 * -1 + -12z * -1] = 2 + (3z + 0)
[-6 + 12z] = 2 + (3z + 0)

Reorder the terms:
-6 + 12z = 2 + (0 + 3z)
Remove the zero:
-6 + 12z = 2 + (3z)
-6 + 12z = 2 + (3z)

Solving
-6 + 12z = 2 + (3z)

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '(-3z)' to each side of the equation.
-6 + 12z + (-3z) = 2 + (3z) + (-3z)

Combine like terms: 12z + (-3z) = 9z
-6 + 9z = 2 + (3z) + (-3z)

Combine like terms: (3z) + (-3z) = 0
-6 + 9z = 2 + 0
-6 + 9z = 2

Add '6' to each side of the equation.
-6 + 6 + 9z = 2 + 6

Combine like terms: -6 + 6 = 0
0 + 9z = 2 + 6
9z = 2 + 6

Combine like terms: 2 + 6 = 8
9z = 8

Divide each side by '9'.
z = 0.8888888889

Simplifying
z = 0.8888888889

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